From 5141d4355ec2c7ac72d61d5d311c7d4df54fb2e2 Mon Sep 17 00:00:00 2001 From: adhoore <72702990+adhoore@users.noreply.github.com> Date: Thu, 21 Oct 2021 20:45:06 +0200 Subject: [PATCH] extremities: Fix typo "cubic -> quadratic" (#330) Co-authored-by: Alexander D'hoore --- docs/chapters/extremities/content.en-GB.md | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/docs/chapters/extremities/content.en-GB.md b/docs/chapters/extremities/content.en-GB.md index a7461348..6b624ebb 100644 --- a/docs/chapters/extremities/content.en-GB.md +++ b/docs/chapters/extremities/content.en-GB.md @@ -4,7 +4,7 @@ Now that we understand (well, superficially anyway) the component functions, we ### Quadratic curves: linear derivatives. -The derivative of a quadratic Bézier curve is a linear Bézier curve, interpolating between just two terms, which means finding the solution for "where is this line 0" is effectively trivial by rewriting it to a function of `t` and solving. First we turn our cubic Bézier function into a quadratic one, by following the rule mentioned at the end of the [derivatives section](#derivatives): +The derivative of a quadratic Bézier curve is a linear Bézier curve, interpolating between just two terms, which means finding the solution for "where is this line 0" is effectively trivial by rewriting it to a function of `t` and solving. First we turn our quadratic Bézier function into a linear one, by following the rule mentioned at the end of the [derivatives section](#derivatives): \[ \begin{aligned}