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typo

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Pomax
2017-04-11 22:06:45 -07:00
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components/sections/pointvectors3d/content.en-GB.md
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@@ -28,7 +28,7 @@ First up: we need to actually *find* that axis of rotation. As it turns out, thi
\end{bmatrix} \right )
\]
(Note that the order of operations matters for cross products: we compute **t'**×**t**, because if we compute **t**×**t'** we'll be computing the samerotation axis but represented by a vector in the opposite direction, so our final normal will actually be rotated a quarter turn "the wrong way". While correcting that is super easy, literally just taking our final normal and multiplying by -1, why correct after the fact what we can get it right from the start?)
(Note that the order of operations matters for cross products: we compute **t'**×**t**, because if we compute **t**×**t'** we'll be computing the same axis of rotation, but represented by a vector in the opposite direction, so our final normal will actually be rotated a quarter turn "the wrong way". While correcting that is super easy, literally just taking our final normal and multiplying by -1, why correct after the fact what we can get it right from the start?)
Note that the cross product does not yield a normalized vector, so we have to do this manually. We already saw how to do this in the above section, though: