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components/sections/matrix/content.en-GB.md
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We can also represent Bézier as matrix operations, by expressing the Bézier formula as a polynomial basis function, the weight matrix, and the actual coordinates as matrix. Let's look at what this means for the cubic curve:
\[
B(t) = P_1 \cdot (1-t)^3 + P_2 \cdot 3 \cdot (1-t)^2 \cdot t + P_3 \cdot 3 \cdot (1-t) \cdot t^2 + P_4 \cdot t^3
B(t) = P_1 \cdot (1-t)^3 + P_2 \cdot 3 \cdot (1-t)^2 \cdot t + P_3 \cdot 3 \cdot (1-t) \cdot t^2 + P_4 \cdot t^3
\]
Disregarding our actual coordinates for a moment, we have:
\[
B(t) = (1-t)^3 + 3 \cdot (1-t)^2 \cdot t + 3 \cdot (1-t) \cdot t^2 + t^3
B(t) = (1-t)^3 + 3 \cdot (1-t)^2 \cdot t + 3 \cdot (1-t) \cdot t^2 + t^3
\]
We can write this as a sum of four expressions: