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Bézier (t) = B (t) · w + B (t) · w + B (t) · w + B (t) · w + ⋯
n,k n,0 0 n,1 1 n,2 2 n,3 3
\mathrmd
───────── Bézier (t) = n · (B (t) - B (t)) · w +
\mathrmdt n,k n-1,-1 n-1,0 0
n · (B (t) - B (t)) · w +
n-1,0 n-1,1 1
n · (B (t) - B (t)) · w +
n-1,1 n-1,2 2
n · (B (t) - B (t)) · w +
n-1,2 n-1,3 3