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B(n,t), w = {A,B,C,D}
B'(n,t), n = 3, w' = {A',B',C'} = {3 · (B-A), 3 · (C-B), 3 · (D-C)}
B''(n,t), n = 2, w'' = {A'',B''} = {2 · (B'-A'), 2 · (C'-B')}
B'''(n,t), n = 1, w''' = {A'''} = {1 · (B''-A'')}