BezierInfo-2/docs/images/snippets/explanation/4bf2d790d2f50bf7767c948e0b9f9822.ascii

 
1次= (1-t) + t                                        
         2                      2
2次= (1-t)  + 2  · (1-t)  · t + t                     
         3             2                       2    3
3次= (1-t)  + 3  · (1-t)   · t + 3  · (1-t)  · t  + t