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Correct bash for...in loop example

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Removed the $ in the variable declaration of the for...in bash loop to correct the code.
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JohnYangSam 2013-09-12 02:01:52 -07:00
parent b28900b889
commit 1528dd4fbe
1 changed files with 1 additions and 1 deletions
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bash.html.markdown
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@ -82,7 +82,7 @@ esac
#For loops iterate for as many arguments given: #For loops iterate for as many arguments given:
#The contents of var $VARIABLE is printed three times. #The contents of var $VARIABLE is printed three times.
for $VARIABLE in x y z for VARIABLE in x y z
do do
echo "$VARIABLE" echo "$VARIABLE"
done done