mirror of
https://github.com/opsxcq/mirror-textfiles.com.git
synced 2025-08-30 16:50:06 +02:00
133 lines
5.4 KiB
Plaintext
133 lines
5.4 KiB
Plaintext
|
|
|
|
___________________________________________________________________________
|
|
| From : KeelyNet BBS | DataLine : (214) 324-3501 |
|
|
| Sysop : Jerry W. Decker | Voice : (214) 324-8741 |
|
|
| File Name : RESMEAS.ASC | Online Date : 05/22/94 |
|
|
| Contributed by : Joel McClain | Dir Category : ENERGY |
|
|
---------------------------------------------------------------------------
|
|
April 25, 1994
|
|
|
|
RESMEAS.ASC Measurement of Resonant frequencies and Harmonics
|
|
|
|
Thanks to information supplied by Gerald O'Doucharty, as compared with
|
|
waveform analyses as determined by the late Mr. Les Brown, we can begin to
|
|
make some progress in the understanding of resonance. I believe that these
|
|
conclusions are in accordance with the discoveries of both Walter Russell,
|
|
in his resonance based chart of the elements, as well as those of John
|
|
Keely.
|
|
|
|
Les Brown dropped a pebble in a bowl of water, and measured the rings which
|
|
resulted. From this, he was able to determine the mathematical
|
|
relationships, which he found to be factors of PI. There is no random
|
|
pattern to the rings.
|
|
|
|
The first ring is equal to the diameter of the pebble. The second ring is
|
|
equal to the diameter of the first ring, times the cube root of PI, or
|
|
1.3313. The third ring is equal to the second ring, also times 1.3313.
|
|
Each ring is a NATURAL HARMONIC of the previous ring.
|
|
|
|
Comparing this with the information supplied by Gerald, we can see that in
|
|
the diatonic scale, the following relationships exist:
|
|
|
|
Whole
|
|
Note Frequency (Hz) 1st Harmonic (UPPER ORDER)
|
|
|
|
C 262 F 349.33 Hz
|
|
D 294.75 G 393.00
|
|
F 349.33 A' 465.06
|
|
G 393.80 C 524 (262 X 2)
|
|
A 436.66 D 581.33 (294.75 X 2)
|
|
C' 524 F 698.66 (349.33 X 2)
|
|
|
|
Semi- Notes
|
|
|
|
E 327.50 A 436.66
|
|
B 491.25 E 654.00 (327.50 X 2)
|
|
|
|
Energies, including radio waves, propagate according to the same ratios,
|
|
based upon the cube root of PI. To an energy researcher, this means:
|
|
|
|
1. Energies are based upon the atomic model. Therefore, the rings which
|
|
surround each atom are based upon the size of the nucleus (pebble), and
|
|
this is the base frequency of the atom. Each ring diameter will be
|
|
determined by the cube root of PI, times the nucleus, and then times
|
|
each ring in succession.
|
|
|
|
2. Once you find the resonant frequency of the nucleus, to resonate the
|
|
atom, you will need to determine the number of rings, and apply the
|
|
correct number of harmonics at the correct frequency. This is true for
|
|
an element, whereas compounds will require each of the fundamental
|
|
frequencies, plus the harmonics.
|
|
|
|
|
|
Page 1
|
|
|
|
|
|
|
|
|
|
|
|
Let's say, for example, that a hydrogen nucleus resonates at G, or 393 Hz.
|
|
|
|
To resonate the aggregate hydrogen atom, you must apply G as well as C, the
|
|
first harmonic, or 524 Hz. If oxygen has a fundamental frequency of A, or
|
|
436 Hz, then you must also apply D, or 589.5 Hz.
|
|
|
|
To resonate water, you would apply 393, 436, 524, and 589.5. However, this
|
|
may not be a "hard and fast" rule, because we know that the highest
|
|
frequency will contain all of the lower frequencies at harmonic intervals,
|
|
but at lower amplitude.
|
|
|
|
Therefore, if a single resonating frequency is used, it will have to be of
|
|
high enough amplitude so that the harmonics are "felt" by the element or
|
|
compound.
|
|
|
|
The frequencies in the above example are based upon the arbitrary values
|
|
assigned in 1939, because they "sound" the best. However, the multiplier
|
|
of the cube root of PI is a constant. So, when you find the fundamental
|
|
frequency of an atom, you can apply this constant to resonate the aggregate
|
|
mass, including the rings.
|
|
|
|
Just multiply the constant times the fundamental freq for the first ring,
|
|
and multiply the constant times the first ring for the second ring, etc.
|
|
|
|
As Gerald pointed out, there are inconsistencies in the man-made chart, so
|
|
experimentation is required. However, Les Brown's constant will apply
|
|
regardless, ONCE THE FUNDAMENTAL FREQUENCY has been determined.
|
|
|
|
Referring to Russell's chart of the elements, we find that the number of
|
|
elements per octave corresponds to the number of whole notes per octave on
|
|
the diatonic scale. Isotopes consist of semi-notes and harmonics.
|
|
|
|
As such, once we begin to analyze elements, we can quantify Russell's
|
|
chart, and determine the exact combination of frequencies for each element,
|
|
isotope and inert gas.
|
|
|
|
Russell obviously knew these correlations, or he would not have been able
|
|
to create the chart in the first place. We have to "reverse engineer" the
|
|
chart to determine the frequencies. Using the cube root of PI, combined
|
|
with experimentation, I believe that that is possible to do.
|
|
---------------------------------------------------------------------------
|
|
KeelyNet (214) 324-3501 is a FREE Alternative Sciences BBS
|
|
Your file contributions and financial support are much appreciated!
|
|
---------------------------------------------------------------------------
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
Page 2
|
|
|
|
|