Add an unified .Site.Config with a services section

Fixes #4751
This commit is contained in:
Bjørn Erik Pedersen
2018-05-22 14:40:06 +02:00
parent 353148c2bc
commit 4ddcf52ccc
4 changed files with 159 additions and 8 deletions

View File

@@ -27,8 +27,6 @@ import (
"strings"
"time"
"github.com/gohugoio/hugo/config/privacy"
"github.com/gohugoio/hugo/resource"
"golang.org/x/sync/errgroup"
@@ -375,8 +373,6 @@ type SiteInfo struct {
RSSLink string
Author map[string]interface{}
LanguageCode string
DisqusShortname string
GoogleAnalytics string
Copyright string
LastChange time.Time
Permalinks PermalinkOverrides
@@ -421,6 +417,17 @@ func (s *SiteInfo) ServerPort() int {
return p
}
// GoogleAnalytics is kept here for historic reasons.
func (s *SiteInfo) GoogleAnalytics() string {
return s.Config.Services.GoogleAnalytics.ID
}
// DisqusShortname is kept here for historic reasons.
func (s *SiteInfo) DisqusShortname() string {
return s.Config.Services.Disqus.Shortname
}
// Used in tests.
type siteBuilderCfg struct {
@@ -1116,7 +1123,7 @@ func (s *Site) initializeSiteInfo() error {
}
}
privacyConfig, err := privacy.DecodeConfig(lang)
siteConfig, err := loadSiteConfig(lang)
if err != nil {
return err
}
@@ -1127,14 +1134,12 @@ func (s *Site) initializeSiteInfo() error {
Social: lang.GetStringMapString("social"),
LanguageCode: lang.GetString("languageCode"),
Copyright: lang.GetString("copyright"),
DisqusShortname: lang.GetString("disqusShortname"),
multilingual: multilingual,
Language: lang,
LanguagePrefix: languagePrefix,
Languages: languages,
defaultContentLanguageInSubdir: defaultContentInSubDir,
sectionPagesMenu: lang.GetString("sectionPagesMenu"),
GoogleAnalytics: lang.GetString("googleAnalytics"),
BuildDrafts: s.Cfg.GetBool("buildDrafts"),
canonifyURLs: s.Cfg.GetBool("canonifyURLs"),
relativeURLs: s.Cfg.GetBool("relativeURLs"),
@@ -1147,7 +1152,7 @@ func (s *Site) initializeSiteInfo() error {
Data: &s.Data,
owner: s.owner,
s: s,
Config: SiteConfig{Privacy: privacyConfig},
Config: siteConfig,
}
rssOutputFormat, found := s.outputFormats[KindHome].GetByName(output.RSSFormat.Name)