Sacharski Bartłomiej bfb28df9a1

[issue-2178] within() passes through $callback return value (#2185) ...

The `within()` function has been modified to pass-through the
return value of the callback function.

It is now possible to write code like:

```php
$out = within('/foo', function () {
  return 'bar';
});
```

The `$out` variable will now contain the value `'bar'`.

If the callback function returns nothing, then the return of
`within()` call will be `null`.

Fixes #2178

2020-10-03 20:49:42 +02:00

..

misc

Changelog parser (#1692)

2018-09-06 13:03:38 +07:00

recipe

[issue-2181] Fix unit tests on non-master branches (#2182)

2020-10-03 10:41:07 +02:00

src

[issue-2178] within() passes through $callback return value (#2185)

2020-10-03 20:49:42 +02:00

bootstrap.php

wip

2020-07-22 19:17:25 +03:00