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remove primes from v/C formulae, they were from an older graphic
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@@ -77,8 +77,8 @@ With `A` found, finding `e1` and `e2` for quadratic curves is a matter of runnin
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\[
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\left \{ \begin{aligned}
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v_1 &= A' - \frac{A' - e_1}{1 - t} \\
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v_2 &= A' - \frac{A' - e_2}{t}
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v_1 &= A - \frac{A - e_1}{1 - t} \\
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v_2 &= A - \frac{A - e_2}{t}
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\end{aligned} \right .
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\]
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@@ -86,8 +86,8 @@ And then reverse engineer the curve's control points:
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\[
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\left \{ \begin{aligned}
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C_1' &= \textit{start} + \frac{v_1 - \textit{start}}{t} \\
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C_2' &= \textit{end} + \frac{v_2 - \textit{end}}{1 - t}
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C_1 &= \textit{start} + \frac{v_1 - \textit{start}}{t} \\
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C_2 &= \textit{end} + \frac{v_2 - \textit{end}}{1 - t}
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\end{aligned} \right .
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\]
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